Already have an account? Get multiple benefits of using own account!
Login in your account..!
Remember me
Don't have an account? Create your account in less than a minutes,
Forgot password? how can I recover my password now!
Enter right registered email to receive password!
How do you find the second minimum spanning tree of a graph? Find the second minimum spanning tree of the following graph.
Ans: The second minimum spanning tree is acquired through replacing the maximum weight edge in the first minimum spanning tree along with next highest weight edge in the graph. In the above graph, the second minimum spanning tree is acquired by replacing (F, G) along with any one of the edge (C, F), (B, D), (D, G). So one of the second minimum spanning tree is {(F, E), (B, C), (E, D), (B, G), (A, G), (C, F)}.
The division algorithm says that when a is divided by b, a unique quotient and remainder is obtained. For a fixed integer b where b ≥ 2, consider the function f : Z → Z given by f(
volume=(1/3)(pi)(radius of base)2(height) curved surface area=(pi)(r)(l), r is radius of base and l is length of straight line connecting apex of cone with point on edge of base
what is 24566x12567=
The product on multiplying - 4bc with 2a is - 8abc. That is, a term with minus sign multiplied with a term having a positive term gives a product which has a minus sign. On the
what is the changen intemperature bewtween the highest and the lowest temperture high-40c low-0c
if the ratio of boys to girls ism 3 to 5, then what percent of the students are boys
what''s it?
Q. Converting Mixed Numbers to Improper Fractions? Ans. Converting a mixed number to an improper fraction is easy. A single multiplication, and then a single addition:
como realizar la i elevavda a la 243
sinX/cscX+secX/cosX=1
Get guaranteed satisfaction & time on delivery in every assignment order you paid with us! We ensure premium quality solution document along with free turntin report!
whatsapp: +91-977-207-8620
Phone: +91-977-207-8620
Email: [email protected]
All rights reserved! Copyrights ©2019-2020 ExpertsMind IT Educational Pvt Ltd