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How can common bus system be constructed
A common bus system could be constructed using multiplexers. These multiplexers select source register whose binary information is then placed on bus. The bus system will multiplex registers of a bit each to produce n-line common bus. The number of multiplexers required to construct bus is equal to n, where n is number of bits in each register. The size of each multiplexer must be k × 1 as it multiplexes k data lines. A bus system can be constructed through 'three-state gates' instead of multiplexers.
How many two-input AND and OR gates are required to realize Y=CD+EF+G ? Ans. Y=CD+EF+G No. of two i/p AND gates=2 No. of two i/p OR gates = 2 One OR gate to OR CD and EF
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