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How can a function return a pointer to its calling routine?
The general form of a function is:
type_specifier function_name(parameter list)
{
body of function;
}
where type_specifier specifies the type of value that the function's return statement returns and the parameter list is a comma-separated list of variable names and types which receive the values of the arguments passed by the call to the function. The purpose of most functions is to either perform a computation and return a value, manipulate information and return a success-or-failure (true or false) value, or perform a strictly procedural routine which produces no value (eg, the exit() function). Functions may be declared to return any valid C data type. If the return type is not specified, it automatically defaults to type int. return causes an immediate exit from a function. It may also be used to return a value. All functions, except those of type void, return a value.
Functions that return pointers are handled just like any other type of function, e.g.:
char * match(char c, char *s)
while(c != *s && *s)
s++;
return(s);
IA-64 instead depends on the compiler for this task. Even before the program is fed into the CPU, the compiler studies the code and makes the similar sorts of decisions that would
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