Highest common factor (hcf), Mathematics

Assignment Help:

We know that a factor is a quantity which divides the given quantity without leaving any remainder. Similar to LCM above we can find a highest common factor (HCF) of the given numbers. Let us look at its definition first. The highest common factor is a quantity obtained from the given quantities and which divides each of them without leaving a remainder. We understand this by taking an example.

Example 

Find the HCF of 49 and 63.

The factors of 49 are 1, 7 and itself. The factors of 63 are 1, 3, 7, 9, 21 and itself. The common factors are 1 and 7. The highest of these is 7, which is the HCF we require.

This is one of the methods to obtain the HCF. This method may prove tedious if we are given bigger numbers and more of them. When such quantities are given, we follow division method as shown below (this method is shown for numbers in the above example).

In this method the first step constitutes dividing the larger quantity by the smaller quantity and subtract it as shown to obtain a remainder (it is not necessary that we ought to get a remainder in all the cases). Then the divisor, 49 (in our case, 49 is the divisor and 63 the dividend, 1 the quotient and 14, the remainder) becomes the dividend and the remainder (14) which we obtained earlier becomes the divisor. We continue doing this until the remainder is 0 as shown below. The last divisor is our HCF.

                                    49) 63 (1
                                          49
                                       ---------
                                         14) 49 (3
                                               42
                                          --------
                                          7) 14 (2
                                              14
                                            -----
                                              0

That is, 7 is the HCF of the numbers 49 and 63.

Now let us consider three quantities and obtain the HCF for them.


Related Discussions:- Highest common factor (hcf)

Using substitution solving polynomial equations, Using Substitution Solving...

Using Substitution Solving Polynomial Equations ? Solve : (x 3 + 4) 2 - 15 (x 3 + 4) + 36 = 0. You might be tempted to multiply everything out and factor. However, there

5th grade, 6 and 3/8 minus 1 and 3/4

6 and 3/8 minus 1 and 3/4

Calculate overhead in bit and time-synchronous communication, 2.    Suppose...

2.    Suppose a file of 35,000 characters is to be sent over a line at 55,000bps. 1. Calculate the overhead in bits and time using asynchronous transmission. Assume 1 start bit

Rates of change and tangent lines in limits, Rates of Change and Tangent Li...

Rates of Change and Tangent Lines : In this section we will study two fairly important problems in the study of calculus. There are two cause for looking at these problems now.

Fractions and equations and illustration, if Mr.Ibias oredered a rectangula...

if Mr.Ibias oredered a rectangular pizza and he wants 2/3 of the pizza to be pepperoni and 1/2 of the pizza with pineapple draw and label the pizza with toppings explain your think

Reason why we start division, Reasons why we start division : The reason w...

Reasons why we start division : The reason we start division by considering the digit in the leftmost place is efficiency and ease . For instance, suppose we divide 417 by 3, we

Angles, in the quadrilateral abcd,ab is 4.3,bd is 5.1,ad is 4.8.angle bdc i...

in the quadrilateral abcd,ab is 4.3,bd is 5.1,ad is 4.8.angle bdc is 20 degrees and angle c is 80 degrees.all dimentions in metres.calculate the unknown sides and angles of the plo

Dividing, If I divide any number do I get the manservant 2 times

If I divide any number do I get the manservant 2 times

Write Your Message!

Captcha
Free Assignment Quote

Assured A++ Grade

Get guaranteed satisfaction & time on delivery in every assignment order you paid with us! We ensure premium quality solution document along with free turntin report!

All rights reserved! Copyrights ©2019-2020 ExpertsMind IT Educational Pvt Ltd