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Prove that the parallelogram circumscribing a circle is rhombus. Ans Given : ABCD is a parallelogram circumscribing a circle. To prove : - ABCD is a rhombus or AB
from 0->1: Int sqrt(1-x^2) Solution) I=∫sqrt(1-x 2 )dx = sqrt(1-x 2 )∫dx - ∫{(-2x)/2sqrt(1-x 2 )}∫dx ---->(INTEGRATION BY PARTS) = x√(1-x 2 ) - ∫-x 2 /√(1-x 2 ) Let
differentiate x to the power 3
what is the consective sum for 2+3
Let E = xy + y't + x'yz' + xy'zt', find (a) Prime implicants of E, (b) Minimal sum for E. Ans: K -map for following boolean expression is given as: Prime implic
1+3+5+7+9+11+13+15+17+19
Example for Comparison Test for Improper Integrals Example: Find out if the following integral is convergent or divergent. ∫ ∞ 2 (cos 2 x) / x 2 (dx) Solution
find the modulus Z=(2-i)(5+i12)/(1+i2)^3
ho we can find the area of diffrent types of polygon
Prove the subsequent Boolean expression: (x∨y) ∧ (x∨~y) ∧ (~x∨z) = x∧z Ans: In the following expression, LHS is equal to: (x∨y)∧(x∨ ~y)∧(~x ∨ z) = [x∧(x∨ ~y)] ∨ [y∧(x∨
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