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GROUP : Group the Related Segments:-
The directive which is used to form logical groups of segments with same purpose or type. This isused to inform the assembler to form a logical group of the following segment names. The assembler passes information to the linker/loader to form the code such that the group declared segments or operands must lie within a 64Kbyte memory segment. Thus all such segments and labels may be addressed by using the same segment base.
PROGRAM GROUP CODE, DATA, STACK
The above statement directs the loader/linker to make an EXE file such that DATA, CODE and STACK segment ought to be lie within a 64kbyte memory segment that named as PROGRAM. For the ASSUME statement, one can utilize the label PROGRAM except than DATA, CODE and STACK as shown.
ASSUME CS: PROGRAM, DS: PROGRAM, SS: PROGRAM.
Flag Manipulation and Processor Control Instructions These instructions control the functioning of available hardware inside the processor chip. These are categorized into thes
ORG : Origin:- The ORG directive directs the assembler to begin the memory allotment for the specific segment, code or block from the declared address in the ORG statement. W
move a byte string ,16 bytes long from the offset 0200H to 0300H in the segment 7000H
1. Write an assembly program that adds the elements in the odd indices of the following array. Use LOOP. What is the final value in the register? array1 DWORD 10, 20, 30, 40, 50, 6
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how i can write a program to divide 2 numbers
Memory Segmentation : The memory in an 8086/8088 based system is organized as segmented memory. In this scheme, the whole physically available memory can be divided into a n
1- Write an assembly program that: a- Defines an array of 10 (word type)elements; b- Finds out the number of negative elements c- Calculate the summation of the posi
use">http://www.raritanval.edu/uploadedFiles/faculty/cs/full-time/Brower/CISY256/2013Spring/CISY256%20Assembly%20Project.pdf use microsoft visual 2010 and http://www.asmirvine.c
how to find out the given number is positive or negative?
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