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In this unit, we will describe a data structure called Graph. Actually, graph is a general tree along no parent-child relationship. In computer science, Graphs have several applications and other fields of science. Generally, graphs represent a comparatively less restrictive relationship among the data items. We will discuss about both undirected graphs & directed graphs. The unit also comprises information on different algorithms which are depending on graphs.
After learning this unit, you have to be able to
Q. Construct a binary tree whose nodes in inorder and preorder are written as follows: Inorder : 10, 15, 17, 18, 20, 25, 30, 35, 38, 40, 50 Preorder: 20, 15, 10
Dequeue (a double ended queue) is an abstract data type alike to queue, where insertion and deletion of elements are allowed at both of the ends. Like a linear queue & a circular q
i want to write code for unification algorithm with for pattern matching between two expression with out representing an expression as alist
Various graph traversal schemes Graph Traversal Scheme. In many problems we wish to investigate all the vertices in a graph in some systematic order. In graph we often do no
In what ways we can get the context sensitive F1 help on a field?' Data element documentation. Data element additional text in screen painter. Using the process on help r
Write down any four applications of queues. Application of Queue (i) Queue is used in time sharing system in which programs with the similar priority form a queu
In this respect depth-first search (DFS) is the exact reverse process: whenever it sends a new node, it immediately continues to extend from it. It sends back to previously explore
Q. Describe the term hashing. Explain any two usually used hash functions. Explain one method of collision resolution.
HSV Colour Model Instead of a set of colour primaries, the HSV model uses colour descriptions that have a more intuitive appeal to a user. To give a colour specification, a use
Ans: A procedure to reverse the singly linked list: reverse(struct node **st) { struct node *p, *q, *r; p = *st; q = NULL; while(p != NULL) { r =q;
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