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si el log de 28 en base 14 es a cuanto es el log de 16 en base 49
-4(2y+x)-5(x-5y) simplify
9.6+5.2=
a^2-b^2-c^2-2bc
1). Using the function: y=y0,(.90)^t-1. In this equation y0 is the amount of initial dose and y is the amount of medication still available t hours after drug is administered. Supp
4(11-5)=
I am stuck on solving this problem a^1/2/a^2. Can anyone help?
y=2/3x-1
x3+y3/x+y
Ask question #MA survey of 400 of recently qualified chartered Accountant revealed that 112 joined industry, 120 stated practice & 160 joined the firms of practicing chartered acco
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