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Find the sum of first 40 positive integers divisible by 6 also find the sum of first 20 positive integers divisible by 5 or 6. Ans:          No's which are divisible by 6 are

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Algebra, If a^n+1 + b^n+1/a^n + b^n is the arithmetic mean of a and b then ...

If a^n+1 + b^n+1/a^n + b^n is the arithmetic mean of a and b then find n. Answer:Arithmatic mean of a,b is =(a+b)/2  from the problem (a+b)/2=(a^n+1 +b ^n+1)/(a^n+b^n)  then (a+

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