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x 4 - 25 There is no greatest common factor here.  Though, notice that it is the difference of two perfect squares. x 4 - 25 = ( x 2 ) 2   - (5) 2 Thus, we can employ

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Solve the linear equation: The equation relating the pressure that is denoted by P, to the force, F & the area, A, over which the force is applied is P =F/A.  Solve this equat

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Solve the subsequent IVP. cos(x) y' + sin(x) y = 2 cos 3 (x) sin(x) - 1 y(p/4) = 3√2, 0 Solution : Rewrite the differential equation to determine the coefficient of t

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