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The positive value of k for which x 2 +Kx +64 = 0 & x 2 - 8x + k = 0 will have real roots . Ans: x 2 + K x + 64 = 0 ⇒ b 2 -4ac > 0 K 2 - 256 > 0 K
Solve -10 cos(3t )= 7 on [-2,5]. Solution Let's first get the inverse cosine portion of this problem taken care of. cos(3 t )= - 7/10 ⇒ 3t = cos -1 ( - 7
the mean and standarddeviation of set a is -x ans s respectively.find the mean and standard deviation of set b
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Explain Pie Charts ? If the frequencies are written as percentages, they can be easily compared using a pie chart. The following is an example of a pie chart using the data fr
What is Chain Based Index Numbers?
Applications of Integrals In this part we're going to come across at some of the applications of integration. It should be noted also that these kinds of applications are illu
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Illustrates that each of the following numbers are solutions to the following equation or inequality. (a) x = 3 in x 2 - 9 = 0 (b) y = 8 in 3( y + 1) = 4 y - 5 Solution
We're here going to take a brief detour and notice solutions to non-constant coefficient, second order differential equations of the form. p (t) y′′ + q (t ) y′ + r (t ) y = 0
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