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QuestionGeneral requirement for Civil Engineering Works in 1992 Edition, Clause 15.09 details that tying wires for strengthening adjacent to and above Class F4 and F5 closes must be stainless steel wires. Give genuine reasons? AnswerIf plain steel tying wires are utilize for reinforcement adjacent to Class F4 and F5 closes, it poses problem of rust staining that may impair appearance of uncovered concrete surfaces. Speed of corrosion of plain steel tying wires is alike to regular steel reinforcement. Yet, for tying wires with extremely tiny diameter, upon long exposure it stands a high possibility of rusting finally and this rust will stain formwork and significantly involve concrete finish. Then, stainless steel tying wires are specified for locations in vicinity of high excellence of finishes to keep away from rust staining by corroded typing wires.
Differences between epoxy grout, cement grout and cement mortar? Epoxy grout comprises epoxy resin, epoxy hardener and aggregates/sand.As a matter of fact, there are various ty
what will be the w/c ration and cement/fly ash ration for the particular mix design
Radial flow pumps for small flows and high heads In radial flow pumps, a diffuser/volute is generally designed at it outlet to convert the kinetic energy obtained during the pu
Question What is the reason that vibrators not used in concrete compaction in piling works ? Answer Concrete for piles must be a high-slump self-compacting mix that i
..describe how u can obtain the length of an inacceble length of a land when a river cross it
Q. Describe Principles of river protection works? Determination of design discharge for a bridge is sometimes required to be based on flood marks left during unprecedented abno
Cross-sectional area of flow (ft 2 ) (A) For rectangular channels = (w)(d). For trapezoidal channels, divide the flow area into two side triangles and one center rectangle, so
influence diagram with example
Resultant Force on a Given Area of a Horizontal Plane By equation, the total vertical force applied to an area A on the plane is: Resultant Force R = ΡA = (lb/ft 2 )(ft 2 )
largest centrifugal pumps
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