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Intuitively, closure of SL 2 under intersection is reasonably easy to see, particularly if one considers the Myhill graphs of the automata. Any path through both graphs will be a
Let L1 and L2 be CGF. We show that L1 ∩ L2 is CFG too. Let M1 be a decider for L1 and M2 be a decider for L2 . Consider a 2-tape TM M: "On input x: 1. copy x on the sec
s->0A0|1B1|BB A->C B->S|A C->S|null find useless symbol?
(c) Can you say that B is decidable? (d) If you somehow know that A is decidable, what can you say about B?
Theorem The class of ?nite languages is a proper subclass of SL. Note that the class of ?nite languages is closed under union and concatenation but SL is not closed under either. N
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i want to do projects for theory of computation subject what topics should be best.
State and Prove the Arden's theorem for Regular Expression
20*2
I want a proof for any NP complete problem
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