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We must also be able to remove common walls between two cells. Write the function removewalls that accepts two cells and removes the wall that is common between the two (hint: any cell will have at most, one wall in common with another).
e.g. >>> cell1=makecell((0,1))
>>> removewalls(cell0,cell1)
>>> cell0
('cell', (0, 0), ['t', 'r', 'l'])
>>> cell1
('cell', (0, 1), ['b', 'r', 'l'])
Hashing collision resolution techniques are a) Chaining, b) Bucket addressing
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