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Function of a Function
Suppose y is a function of z,
y = f(z)
and z is a function of x,
z = g(x)
Since, y depends on z, and z in turn depends on x, y is also a function of x.
Thus, y = f(z)
= f[g(x)]
The derivative of y with respect to x can be obtained as:
The above method is often used to get the derivative of some complicated functions.
meaning
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2(sin 6 ?+cos 6 ?) - 3(sin 4 ?+cos 4 ?)+1 = 0 Ans: (Sin 2 ?)3 + (Cos 2 ?)3-3 (Sin 4 ?+(Cos 4 ?)+1=0 Consider (Sin 2 ?)3 +(Cos 2 ?)3 ⇒(Sin 2 ?+Cos 2 ?)3-3 Sin 2 ?Co
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tan[2x+pie/4]
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