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The functions
{sinmx; cosmx}; m = 0,....∞
form a complete set over the interval x ∈ [ -Π, Π]. That is, any function f(x) can be expressed as a linear superposition of these with a unique set of coecients. For f(x) = x, we have
To show that the above holds for x = 1, study the dierence between the left- and right-hand sides of the equality as a function of the number of terms included in the sum. Write an octave program to compute and plot the truncated sum approximation (expansion vs x) for n =4 and 16 together with the function x. Make a table showing the error (dierence between two sides) for n =1, 2, 4, 16, 64, 256, 1024. Plot the result of the expansion for 2 values of n together with the original function. Comment on your results. You should submit an octave script or function le I can use to reproduce your results and a separate document (plain text le preferred) for your comments.
Show that the radius of the circle,passing through the centre of the inscribed circle of a triangle and any two of the centres of the escribed circles,is equal to the diameter of t
Can you explain that a wave through the origin always has a slope of one or not?
Q. Example of circle graphs? Ans. The United States Government pays obligations annually, called "outlays". Medicare contributes to the health and well being of aged an
2(sin 6 ?+cos 6 ?) - 3(sin 4 ?+cos 4 ?)+1 = 0 Ans: (Sin 2 ?)3 + (Cos 2 ?)3-3 (Sin 4 ?+(Cos 4 ?)+1=0 Consider (Sin 2 ?)3 +(Cos 2 ?)3 ⇒(Sin 2 ?+Cos 2 ?)3-3 Sin 2 ?Co
Q. How to calculate Mode? The mode of a data set is the value that is repeated most often in the data set. It has the highest frequency. There can be one, more than one, or n
Determine the ratio in which the line 2x + y -4 = 0 divide the line segment joining the points A (2,-2) and B (3, 7).Also find the coordinates of the point of division. [Ans:2 :
remainder theorem
Example : Determine the Taylor series for f(x) = e x about x=0. Solution It is probably one of the easiest functions to get the Taylor series for. We just require recallin
20+20
There actually isn't a whole lot to do throughout this case. We'll find two solutions which will form a basic set of solutions and therefore our general solution will be as,
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