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A thin rod of length 1 m is fixed in a vertical position inside a train, which is moving horizontally withconstant acceleration 4 m/s2. A bead can slide on the rod, and friction coefficient between them is 1/2.If the bead is released from rest at the top of the rod, find the time when it will reach at the bottom. Solution) If mass of bead is m;mg-µN=maNow, N=pseudo force due to acceleration of train, which is equal to 4m Newton. => mg-µ(4m)=ma=> g-4µ=a=> a=8ms-2 Using, second equation of motion:1=0.5(8)t2T=0.5sec
Presumptuous that it is understood that the object is in front of the mirror and anything on the other side of the mirror is behind the mirror is the following statement sufficient
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