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Prove the subsequent Boolean expression: (x∨y) ∧ (x∨~y) ∧ (~x∨z) = x∧z Ans: In the following expression, LHS is equal to: (x∨y)∧(x∨ ~y)∧(~x ∨ z) = [x∧(x∨ ~y)] ∨ [y∧(x∨
Explain Similar Figures in similarity ? Similar figures are figures that have the same shape but not necessarily the same size, so the image of a figure is similar to the orig
prove that the composition of two simple harmonic of the same period and in the same straight line is also a simple harmonic motion of the same period.
So far we have considered differentiation of functions of one independent variable. In many situations, we come across functions with more than one independent variable
in regrouping if we have abig number in the end what should i do?add an number on top of it,please help
* 2^(1/2)*4^(1/8)*8^(1/16)*16^(1/32) =
Definition of limit : Consider that the limit of f(x) is L as x approaches a & write this as provided we can make f(x) as close to L as we desire for all x adequately clos
how do we solve multiple optimal solution
40.783-75
how to use a micrometer
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