fraction, Mathematics

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If tan2x.tan7x=1 , tan9x = (tan7x + tan2x)/(1 - tan7x*tan2x) here its give...

tan9x = (tan7x + tan2x)/(1 - tan7x*tan2x) here its given 1 - tan2x*tan7x= 0 implies tan9x = infinity since tan9x = (3tan3x - tan^3(3x))/(1 - 3tan^2 (3x)) = infinity implies

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