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ABC is a right-angled isosceles triangle, right-angled at B. AP, the bisector of ∠BAC, intersects BC at P. Prove that AC 2 = AP 2 + 2(1+√2)BP 2 Ans: AC = √2AB (Sinc
JUST IS WHOLE
Polar Coordinates Till this point we've dealt completely with the Cartesian (or Rectangular, or x-y) coordinate system. Though, as we will see, this is not all time the easie
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