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The positive value of k for which x 2 +Kx +64 = 0 & x 2 - 8x + k = 0 will have real roots . Ans: x 2 + K x + 64 = 0 ⇒ b 2 -4ac > 0 K 2 - 256 > 0 K
Graph f ( x ) = e x and g ( x ) = e - x . Solution There actually isn't a lot to this problem other than ensuring that both of these exponentials are graphed somewhere.
do we calculate midpoints from classes or from class boundaries
Before we look at simultaneous equations let us brush up some of the fundamentals. First, we define what is meant by an equation. It is a statement which indicate
Find the sum og series 1+(1+3)+(1+3+5)+.......+(1+3+...+15+17)=
what is the perimeter of a rhombus
a man in rested rupee 800 is buying rupee 5 shares and then are selling at premium of rupee 1.15. He sells all the shares.find profit
if tan theta =1,find the value of sin4 theta + cos4 theta
write a short note on shares and dividend under the following heading: shares ,type of shares,face/nominal value of shares.
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