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if the roots of a quadratic equation are (-2+sqrt 6) and (-2-sqrt 6), what is the equation in ax^2+bx+c=0 form?
-2
The slope is -3 and the y-intercept is 4. How do I find a relation in the form y=mx+b which has a solution set line satisfying the given conditions?
how to find the distance between -2 and 3 on a number line
Solve following equations. 1/(x+1) = 1- (5/2x - 4) Solution Just like along with the linear equations the primary thing which we're going to
how do you solve x5 * x3
i Need Help on Solve for X
{5x-4y=-21} {-2x+4y=18}
Simplify 3(x-2)to the second -2(x+1)
what is the principal square root of the square number?
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