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Format of Control Register
The format for the control register is given in Figure. Bit 0 of this register might be one before data may be output and bit two might be one before data can be received. Programmed answering of a modem is accomplished by setting bit 1 to 1 since this forces the DTR pin to zero and the complement of DTR is usually linked to the CD line from the modem. Bit 3 equal to 1 force TxD to 0, thus causing break characters to be transmitted. Setting bit 4 to 1 causes every error bits in the status register to be cleared (the bits that are set when overrun, framing and parity errors occur). Bit 5 is utilized for sending a Request to send signal to a modem. If the complement of the RTS pin is linked to a modem's CA line, then a one put in bit5 will cause the CA line to go high. Setting bit 6 causes the8251 A to be reinitialized and the reset sequence to be re-entered (for instance a return is made to the top of the flowchart shown in Figure and the next output will be to the mode register). Bit seven is utilized just with the synchronous mode. When set, it causes the 8251A to start a bit-by-bit search for a sync character or sync characters.
INTO : Interrupt on Overflow:- It is executed, when the overflow flag OF is set. The new contents of IP and CS register are taken from the address 0000:0000 as described in INT
Read Architecture: Look Through Main memory that located is conflicting the system interface. The least concerning feature of this cache unit is that it remain between the proc
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Write a program to do the following: 1. Print your name 2. Using a bottom testing loop, prompt the user to enter a number from 1 to 5. If the number entered is not 1..5, pri
errorlevel -302 ;prevents error code for this chipset __config 0x373A ;chip config PIC spec page 146 processor 16F877A ;chipset reset code
LDS/LES Instruction execution : LAHF : Load AH from Lower Byte of Flag: - This instruction loads the AH register with the lower byte of the flag register. This instruction ca
I need help with assembly programing
I need to generate a random number bby using 8086 assembly language
Entering a Program In this section, we will explain the procedure for entering a small program on IBM PC with DOS operating system. Assume a program of addition of 2 bytes, as
DQ: Define Quad word:- This directive is taken in use to direct the assembler to reserve 4 words (8 bytes) of memory for the specified variable and can initialise it having
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