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Format of Control Register
The format for the control register is given in Figure. Bit 0 of this register might be one before data may be output and bit two might be one before data can be received. Programmed answering of a modem is accomplished by setting bit 1 to 1 since this forces the DTR pin to zero and the complement of DTR is usually linked to the CD line from the modem. Bit 3 equal to 1 force TxD to 0, thus causing break characters to be transmitted. Setting bit 4 to 1 causes every error bits in the status register to be cleared (the bits that are set when overrun, framing and parity errors occur). Bit 5 is utilized for sending a Request to send signal to a modem. If the complement of the RTS pin is linked to a modem's CA line, then a one put in bit5 will cause the CA line to go high. Setting bit 6 causes the8251 A to be reinitialized and the reset sequence to be re-entered (for instance a return is made to the top of the flowchart shown in Figure and the next output will be to the mode register). Bit seven is utilized just with the synchronous mode. When set, it causes the 8251A to start a bit-by-bit search for a sync character or sync characters.
Memory Mapped I/O Memory I/O devices are mapped into the system memory map with ROM and RAM. To access a hardware device, simply write or read to those 'special' addresse
The 486 Introduced in the year 1989 the 80486 did not feature any radically new processor technology. Instead, it joints a 386 processor, a cache memory controller and a math c
00h-1h
INT N : Interrupt Type N:- In the interrupt structure of 8086/8088, 256 interrupts are distinct equivalent to the types from OOH to FFH. When an instruction INT N is executed,
1. Write a program that calculates the Fibonacci series: 1, 1, 2, 3, 5, 8, 13, ….. (Except for the first two numbers in the sequence, each number is the sum of the preceding two n
Write an assembly program that will compute and output tuition cost: a. accept keyboard input of the number of credit hours taken b. accept keyboard input of the type of classes 1
what will be the value of EAX after following instructions execute? mov bx, 0FFFFh and bx, 6Bh
Difference between div and idiv
write a program using assembly language that print your name
Assume that the registers are initialized to EAX=12345h,EBX =9528h ECX=1275h,EDX=3001h sub AH,AH sub DH,DH mov DL,AL mov CL,3 shl DX,CL shl AX,1 add DX,AX
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