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Format of Control Register
The format for the control register is given in Figure. Bit 0 of this register might be one before data may be output and bit two might be one before data can be received. Programmed answering of a modem is accomplished by setting bit 1 to 1 since this forces the DTR pin to zero and the complement of DTR is usually linked to the CD line from the modem. Bit 3 equal to 1 force TxD to 0, thus causing break characters to be transmitted. Setting bit 4 to 1 causes every error bits in the status register to be cleared (the bits that are set when overrun, framing and parity errors occur). Bit 5 is utilized for sending a Request to send signal to a modem. If the complement of the RTS pin is linked to a modem's CA line, then a one put in bit5 will cause the CA line to go high. Setting bit 6 causes the8251 A to be reinitialized and the reset sequence to be re-entered (for instance a return is made to the top of the flowchart shown in Figure and the next output will be to the mode register). Bit seven is utilized just with the synchronous mode. When set, it causes the 8251A to start a bit-by-bit search for a sync character or sync characters.
Comparison between 8086 and 8088 All the changes in 8088 above 8086 are indirectly or directly related to the 8-bit, 8085 compatible data and control bus interface. 1) The p
Program : A program to move a string of the data words from offset 2000H to offset 3000H the length of the string is OFH. Solution : For writing this program, we will use
Ask(2) Write a program to mask bits D3D2D1D0 and to set bits D5D4 and to invert bits D7D6 of the AX register question #Minimum 100 words accepted#
Fourth Generation Microprocessor : The single chip 32-bit microprocessor was introduced in 1981 by Intel as iAPX 432. The other 4th generation microprocessors were; Hewlett
Pin diagram of 8088 : The pin diagram of 8088 is shown in given figure. Most of the 8088 pins and their functions are exactly similar to the corresponding pins of 8086. Hence
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.MODEL SMALL .STACK 100H .DATA PROMPT DB \''The 256 ASCII Characters are : $\'' .CODE MAIN PROC MOV AX, @DATA ; initialize DS MOV DS, AX
You have to write a subroutine (assembly language code using NASM) for the following equation.
Program : Write an assembly program to find out the largest number from a given unordered array of 8-bit numbers that stored in the locations starting from a known address. S
Interrupt Priority Management The interrupt priority management logic indicated in given figure can be implemented in several ways. It does not required to be present in system
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