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Force required to start the roller:
A roller shown in the figure given below is of mass 150Kg. What force T is required to start the roller over block A?
Sol.: Let R be reaction given by block to the roller, and is to act at point A subtends an angle of ? as shown in the figure given below,
For finding angle θ ,
Sin θ = 75/175 = 0.428
= 25.37°
Apply lami's theorem at 'A', as the body is in equilibrium
T/sin(90° + 25.37°) = 150 × g/ sin(64.63° + 65°)
T = [150 × g × sin(90° + 25.37°)]/ sin(64.63° + 65°)
T = 1726.33N
can anybody tells me about t-s n p-h diagram? just about the concept and working principle.can anybody help me? thank you. :)
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