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As with the first order system, there is a general differential equation that governs the response of a second order system. The equation is of the form:
Where:
So how is the second order differential equation for the spring mass damper generated?
Well, if an input is applied to the mass, the equation of motion for the system can be written as:
The general equation for a second order system can be manipulated to give the equation above and vice versa.
Performing the numerical integration for the second order system
The second order equation order is dealt with by rewriting the equation as pair of first order equations. The numerical integration can be performed in a similar way to the first order system where:
Of course as all the hardware information is available or selected by the engineer, the value for (d2y/dz2) can be calculated by manipulating the equation of motion.
Arrianna spended $5,500 at 7.5% p.a. compounded quarterly for 'n' years. At the end of 'n' years, Arrianna got back $12,000. What is the value of n? (Approximate your answer in yea
In estimating the cost of a pile of bricks measured as 2m*15m*1.2m,tape is stretched 1% beyond the standard length if the count is 450 bricks to 1m^3 and bricks cost $530 per 1000,
can you tell me what is the physical intrepetation of convolution theorm or convolution integral?
The integral has an exact answer, viz., sinc(pfT). As T®¥ the sinc function tends to zero. Divide the region from -T/2 to T/2 into N equal parts and sum the rectangles on b
i need a quote in analytical methods for engineers (Algebraic methods)
With the help of energy bands explain how conduction takes place in conductors. On the basis of energy band materials are categorized as conductor is given below: Conducto
a) Use divided differences to ?nd the polynomial (in nested form) that interpolates the data b) Add the data point x = 6, y = -20 and hence estimate y for x = 2.
advantages of langmuir adsorption theory
In closed system 0.3kg of gas at 373K is expanded isothermally and reversibly from 1 mpa pressure to 200 kp. Given that cv= 718 j/kg k and R= 287 j/kgk.
parabola
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