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Firecracker Welding
This is a semi automatic version of SMAW. A specially designed heavy - coated electrode, which can be of any length upto 2 m, is laid on the seam of a grooved butt joint or along the root of a tee joint. It is then clamped down with a water - cooled copper bar heavy square section, which is grooved to accommodate the electrode. The copper bar is nearly as long as the electrode. The bare end is clamped in a holder. The arc is struck at the striking end and the electrode gradually consumes by itself, making the butt or fillet weld of the same length as the electrode. The copper block helps to prevent overheating of the electrode and to maintain intimate contact between the electrode and the joint.
Calculate the Spindle Speed by (a) HSS tool (b) Carbide Tool Calculate the spindle speed (N) if a C 20 steel job of 50 mm dia is to be turned by (a) HSS tool and (b) Carbide T
These parts of joints are used to connect two rods, which are under compressive or tensile stress. The ends of the rods are in the manner of a socket and shaft that fit together an
formulae for finding gross torque developed by the armeture
Review questions condition of equilibrium grade 11 unit 7
Q. Radiographic examination of welded joints? Radiographic examination (RT) of welded joints shall be performed as required by the Code. Acceptance criteria shall be in accord
A simply supported beam of length 5m takes a uniformly increasing load of 800 N/m at one end to 1600 N/m at the other end. Draw the shear force and the Bending moment diagrams for
Q. Carbon and Low Alloy Steels for Welding? All welding of pressure retaining equipment must be completed as per the respective code, typically ANSI/ASME B31.1 or Section VIII
Determine the deflection of the spring: A close coiled helical spring deflects 25 mm under a certain axial load. Determine the deflection of the second spring under the simila
Creep in belt drive
Define Cutting Parameters - Depth of Cut It is the thickness of metal removed by grinding wheel in one traverse stroke (lengthwise) t=depth of cut =D 1 -D 2 / 2
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