Already have an account? Get multiple benefits of using own account!
Login in your account..!
Remember me
Don't have an account? Create your account in less than a minutes,
Forgot password? how can I recover my password now!
Enter right registered email to receive password!
Finite Population Correction Factor Or Fpcf)
If a specified population is relatively of small size and sample size is more than 5 percent of the population then the standard error must be adjusted by multiplying it by the finite population correction factor as:
FPCF is described by =
Whereas N = population size
n = sample size
Illustration
A manager wants an estimate of sales of salesmen in his company. A random sample 100 out of 500 salesmen is chosen and average sales are found to be Shs. 75,000. If a sample standard deviation is Shs. 15000 then determines the population mean at 99 percent level of confidence
Solution
Now N = 500, n = 100, x¯ = 75000 and S = 15000
Here
Standard error of mean
Sx¯ = (s/√n) * {}
= (15,000/√100) * (√ {(500 - 100)/(500 - 1)})
= (15,000/10) * (0.895)
Sx¯ = 1342.50 at 99 percent level of confidence
Population mean = x¯ ± 2.58 Sx¯
=shs 75000 ± 2.58(1342.50)
=shs 75000 ± 3464
= Shs 71536 to 78464
Here we learn: 1) Discussed what counting means, and stressed that it is not the ability to recite number names. 2) Talked about the need for a child to understand several pr
Simplify following and write the answers with only positive exponents. (-10 z 2 y -4 ) 2 ( z 3 y ) -5 Solution (-10 z 2 y -4 ) 2 ( z 3 y ) -5
3+5
time=2.82/4000
E1) Do you agree that multiplication and division should be learnt intermeshed with each other, or not? Give reasons for your answer. E2) How would you explain to children wh
report on shares and dividend using newspaper
Test of hypothesis about the population mean When the population standard deviation (S) is identified then the t statistic is defined as t = ¦(x¯ - µ)/ S x¯ ¦
Before we find into finding series solutions to differential equations we require determining when we can get series solutions to differential equations. Therefore, let's start wit
solve the equation 540+115 using the NOWA method
if I read 6 hours of spring break how many minutes did read
Get guaranteed satisfaction & time on delivery in every assignment order you paid with us! We ensure premium quality solution document along with free turntin report!
whatsapp: +91-977-207-8620
Phone: +91-977-207-8620
Email: [email protected]
All rights reserved! Copyrights ©2019-2020 ExpertsMind IT Educational Pvt Ltd