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Finite Population Correction Factor Or Fpcf)
If a specified population is relatively of small size and sample size is more than 5 percent of the population then the standard error must be adjusted by multiplying it by the finite population correction factor as:
FPCF is described by =
Whereas N = population size
n = sample size
Illustration
A manager wants an estimate of sales of salesmen in his company. A random sample 100 out of 500 salesmen is chosen and average sales are found to be Shs. 75,000. If a sample standard deviation is Shs. 15000 then determines the population mean at 99 percent level of confidence
Solution
Now N = 500, n = 100, x¯ = 75000 and S = 15000
Here
Standard error of mean
Sx¯ = (s/√n) * {}
= (15,000/√100) * (√ {(500 - 100)/(500 - 1)})
= (15,000/10) * (0.895)
Sx¯ = 1342.50 at 99 percent level of confidence
Population mean = x¯ ± 2.58 Sx¯
=shs 75000 ± 2.58(1342.50)
=shs 75000 ± 3464
= Shs 71536 to 78464
un=63-4n
Extrema : Note as well that while we say an "open interval around x = c " we mean that we can discover some interval ( a, b ) , not involving the endpoints, such that a Also,
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