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Finite Population Correction Factor Or Fpcf)
If a specified population is relatively of small size and sample size is more than 5 percent of the population then the standard error must be adjusted by multiplying it by the finite population correction factor as:
FPCF is described by =
Whereas N = population size
n = sample size
Illustration
A manager wants an estimate of sales of salesmen in his company. A random sample 100 out of 500 salesmen is chosen and average sales are found to be Shs. 75,000. If a sample standard deviation is Shs. 15000 then determines the population mean at 99 percent level of confidence
Solution
Now N = 500, n = 100, x¯ = 75000 and S = 15000
Here
Standard error of mean
Sx¯ = (s/√n) * {}
= (15,000/√100) * (√ {(500 - 100)/(500 - 1)})
= (15,000/10) * (0.895)
Sx¯ = 1342.50 at 99 percent level of confidence
Population mean = x¯ ± 2.58 Sx¯
=shs 75000 ± 2.58(1342.50)
=shs 75000 ± 3464
= Shs 71536 to 78464
inverse rule of x3-5
CONCEPT OF NUMBER LINE
Two cars begin 500 miles apart. Car A is into the west of Car B and begin driving to the east (that means towards Car B) at 35 mph & at the similar time Car B begin driving south
Explain with the help of number line (-6)+(+5)
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01010011 01100101 01101101 01110000 01100101 01110010 00100000 01000110 01101001 00100001
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Question. Determine the position and nature of stationary points of the function? f(x,y)= y/x -x 2 +y 2
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