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Finding the Equation of a line, Given a Slope and a Point ?
Find the equation of a line with slope m = 2, which passes through the point (-1, -3).
Solution:
Use the point-slope form:
y - y1 = m(x - x1 )
With m = 2 and (x1 ,y1 ) = (-1, -3). Substitute for m, x1 , and y1:
y - ( -3) = 2(x - ( -1)).
Simplify:
y + 3 = 2x + 2
y = 2x - 1.
(This is the slope-intercept form.)
(a+b)''2
If a+b+c = 3a , then cotB/2 cotC/2 is equal to
10:30:45
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