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Finding Absolute Extrema :Now it's time to see our first major application of derivatives. Specified a continuous function, f(x), on an interval [a,b] we desire to find out the absolute extrema of the function. To do this we will requierd many of the ideas which we looked at in the previous section.
Firstly, as we have an interval and we are considering that the function is continuous the Extreme Value Theorem described that we can actually do this. it is a good thing of course. We don't desire to be trying to determine something that may not exist.
Next, we illustrated in the earlier section that absolute extrema can take place at endpoints or at relative extrema. Also, from Fermat's Theorem we know that the list of critical points is also a list of all probable relative extrema. Thus the endpoints along with the list of all critical points will actually be a list of all probable absolute extrema.
Now we just required to recall that the absolute extrema are nothing more than the largest & smallest values which a function will take thus all that we actually required to do is get a list of possible absolute extrema, plug these points into our function and then recognize the largest & smallest values.
From the data given below calculate the value of first and third quartiles, second and ninth deciles and forty-fifth and fifty-seventh percentiles.
FORMULAS DERIVATION
You are painting the surface of a silo that has a diameter of 16 ft and height of 50 ft. What is the net surface area to be painted? Consider the top of the silo is 1/2 a sphere
kolushushi borrowed tsh 250000/- and paid135000/- as interest in 3 years. what rate of interest was paid
Verify Liouville''''s formula for y "-y" - y'''' + y = 0 in (0, 1) ?
provide a real-world example or scenario that can be express as a relation that is not a function
the mass of a container is 5.81kg when full with sugar .the mass of container is 3.8kg when 3/8 of the sugar is removed.what is the mass of empty container
Simplify the following expression and state the coefficient of each variables (a)6m-4-2m+15 (b)4x+6y-3x+5y
1) Compute the center of mass of the solid of unit density 1 bounded (in spherical coordinates) by p=1 and by φ is greater than or equal 0 and less than or equal pi/4
why arcsin(sinq)=pi-q [pi/2 3pi/2]
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