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A right triangle whose sides are 15 cm and 20 cm is made to revolve about its hypotenuse. Find the volume and surface area of the double cone so formed.
(Ans : 3768cu.cm,1318.8 Sq.cm)
Ans: BC = √152 + √202
= 25 cm
Apply Py. Th to right ΔOAB & OAC to get OB = 9cm OA = 12cm
Vol of double cone = vol of CAA1 + vol of BAA1
= 1/3 π × 122 × 16 + 1/3 π × 122 × 9
= 3768 cm3
SA of double cone = CSA of CAA1 + CSA of BAA1
= π × 12 × 20 +π × 12 × 15
= 1318.8 cm3
(2a+8b)
table of 12
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