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Find the third vertex of a triangle if its two vertices are (-1, 4) and (5, 2) and mid point of one side is (0, 3). (Ans: (-5, 4) or (1, 2))
Ans : Let the third vertex be (x, y)
If (0,3) is mid point of BC then
x + 5/2 =0 (or) x = - 5
y + 2/2 =3 y=4. (-5, 4)
If (0,3) is mid point of AC then
x - 1/2 =0 x=1 y + 4/2 =3 y + 4 = 6 y = 2 (1, 2)
∴ (-5. 4) or (1, 2) are possible answers.
Since we are going to be working almost exclusively along with systems of equations wherein the number of unknowns equals the number of equations we will confine our review to thes
all basic knowledge related to geometry
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