Find the sides of the two squares, Mathematics

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The sum of areas of two squares is 468m2  If the difference of their perimeters is 24cm, find the sides of the two squares.

Ans:    Let the side of the larger square be x.

Let the side of the smaller square be y. APQ x2+y2 = 468

Cond. II          4x-4y = 24

x - y = 6

⇒ x = 6 + y

x2  + y2 = 468

⇒ (6+y)2 +y2 = 468

on solving we get y = 12

x = (12+6) = 18 m

∴ sides are 18m & 12m.


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