Find the shell temperature, Physics

Assignment Help:

Q. Find the shell temperature?

In a shell-and-tube heat exchanger, one fluid passes through a central tube while another fluid flows through an outer shell in the opposite direction. The purpose is to heat the fluid passing through the central tube. It is possible to maintain a constant temperature TS of the outer shell fluid by continually condensing a vapor (for example, steam) along the length of the shell.

By integrating a heat balance equation along the tube, it is possible to relate the length L and diameter D of the heat exchanger to the input temperature T1 and output temperature T2:

1504_Physical Setting.png

and where

P  = viscosity of the fluid (depends on T)

k  = thermal conductivity of the fluid (depends on T)

cp  = specific heat of the fluid (depends on T)

m  = flow rate of the fluid through the tube

D  = diameter of the tube

The temperature dependence of the specific heat, viscosity, and thermal conductivity depend on the working fluid and, therefore, upon temperature, T. For this assignment use:

21_Physical Setting1.png

The thermal conductivity data,  () kT , has been evaluated, experimentally, at only a few data (temperature) points.  We have decided, therefore, to use a polynomial approximation and we do so with the full knowledge that our experimental data may contain errors.

where T is measured in degrees Fahrenheit (oF) throughout.

The Problem:

Given the values of D, m, T1, T2, L, determine the necessary shell temperature, TS. In particular, given that D =1.95 inches (convert to ft), m =25 lb/hr, 170TF, and the heat exchanger length is L = 5 ft, find the shell temperature TS needed to heat the output gas to T2 = 360oF.

2233_Physical Setting2.png


Related Discussions:- Find the shell temperature

Inductor construction, An inductor is generally constructed as a coil of co...

An inductor is generally constructed as a coil of conducting material, characteristically copper wire, wrapped around a core either of air or a ferromagnetic material. Core materia

Explain interference of light, When two waves of exactly similar frequency ...

When two waves of exactly similar frequency (coming from two coherent sources) travels in a medium, in the similar direction simultaneously then because of their superposition, at

Rocket observation, At a distance of 4,000 ft from the launch site, a spect...

At a distance of 4,000 ft from the launch site, a spectator is observing a rocket being launched. If the rocket lifts off vertically and is rising at a speed of 600 ft/sec when it

Steel, Steel: Steel contains iron with a small percentage of carbon added ...

Steel: Steel contains iron with a small percentage of carbon added it. Iron itself is not very strong but the additions of small percentage of carbon in it decrease the ductility

Equatorial line and neutral point, Equatorial Line and Neutral point: ...

Equatorial Line and Neutral point: Equatorial Line: The imaginary line joining the centre of mass  and perpendicular to the line joining the poles of a bar magnet is called th

Mass of a sphere of diameter 1cm whose density is 900 kg/m^3, mass=volume *...

mass=volume * density.By using this formula we can find the mass of sphere. Volume of sphere=(4/3)pi*r^3 V=(4/3)*3.14*(1*10^-2)^3=4.187*10^-6 Mass=(4.187*10^-6)*900=3768*10^-6kg

Explain transmitters and receivers, Explain Transmitters and Receivers Yo...

Explain Transmitters and Receivers Your radio is able to give you the news or play music because it can receive signals that are transmitted by radio stations. Radio waves are el

Photoelectric cell, A device which changes light energy into electrical ene...

A device which changes light energy into electrical energy is known as photoelectric cell. It is also known as photocell or electric eye.

Write Your Message!

Captcha
Free Assignment Quote

Assured A++ Grade

Get guaranteed satisfaction & time on delivery in every assignment order you paid with us! We ensure premium quality solution document along with free turntin report!

All rights reserved! Copyrights ©2019-2020 ExpertsMind IT Educational Pvt Ltd