Find the probability of having 53 sundays in leap year , Mathematics

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Find the probability of having 53 Sundays in

(i) a leap year                           (ii) a non leap year       (Ans:2/7 , 1/7 )

Ans:          An ordinary year has 365 days i.e. 52 weeks and 1 day

This day can be any one of the 7 days of the week.

∴ P(that this day is Sunday) = 1/7

Hence, P(an ordinary year has 53 Sunday) = 1/7

A leap  year 366 days i.e. 52 weeks and 2 days

This day can be any one of the 7 days of the week

∴ P (that this day is Sunday) = 2/7

Hence, P(a leap year has 53 Sunday) = 2/7

 

 

 


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