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Q. Suppose Jessica has 10 pairs of shorts and 5 pairs of jeans in her drawer. How many ways could she pick out something to wear for the day? What is the probability that she picks out shorts (assuming she picks out her clothing blindfolded)?
Solution:
Jessica could choose a pair of shorts in 10 ways or a pair of jeans in 5 ways, but she can't choose both types of clothing to wear today. Thus she can choose her clothes in 10 + 5 = 15 ways.
Since there are 10 pairs of shorts in the drawer, the probability of Jessica choosing one of them is
If the expression 9y - 5 represents a certain number, which of the following could NOT be the translation? a. five less than nine times y b. five less than the sum of 9 and y c
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Expected Value of Perfect Information In the above problems we have used the expected value criterion to evaluate the decisions under the conditions of risk. But, as long as un
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