Find the polynomial g(x), Mathematics

Assignment Help:

On dividing the polynomial 4x4 - 5x3 - 39x2 - 46x - 2 by the polynomial g(x) the quotient is x2 - 3x - 5 and the remainder is -5x + 8.Find the polynomial g(x). (Ans:4 x2+7x+2)

Ans:    p(x) = g (x) q (x) + r (x)

g(x) =px) - rx)/q( x)

let p(x) = 4x4 - 5x3 - 39x2 - 46x - 2 q(x) = x2 - 3x - 5 and r (x) = -5x + 8

now p(x) - r(x) = 4x4 - 5x3 - 39x2 - 41x - 10

when px) - rx)/qx)

∴ g(x) = 4x2 + 7x + 2

= 4x2 + 7x +2


Related Discussions:- Find the polynomial g(x)

Laws of indicies in fraction.., help to solve the laws of indicies chapter ...

help to solve the laws of indicies chapter 9c book 3 high school example19to the power3_2 what is answer

ALGEBRA, FIND PRODUCT (-41)*(102)

FIND PRODUCT (-41)*(102)

Example of integration strategy - integration techniques, Evaluate the subs...

Evaluate the subsequent integral. ∫ (tan x/sec 4 x / sec 4 x)  dx Solution This kind of integral approximately falls into the form given in 3c.  It is a quotient of ta

Series, find the series of the first twenty terms

find the series of the first twenty terms

How to find total no. of unordered pairs , How to find total no. of unorder...

How to find total no. of unordered pairs of disjoint subsets of a finite set? Solution) Suppose A and B are two such disjoint subsets of the set S. Then every element can go into

Objectives of multiplication and division, Objectives After reading t...

Objectives After reading this unit, you should be able to 1. Explain the meaning of multiplication / division and interpret it in different contexts; 2. Convert symbo

Trig, without using a calculator how would you know is cos theta(20) is gre...

without using a calculator how would you know is cos theta(20) is greater than cos theta (35)

Write Your Message!

Captcha
Free Assignment Quote

Assured A++ Grade

Get guaranteed satisfaction & time on delivery in every assignment order you paid with us! We ensure premium quality solution document along with free turntin report!

All rights reserved! Copyrights ©2019-2020 ExpertsMind IT Educational Pvt Ltd