Find the magnitude of force:
Q: The two parallel forces are acting at point A and B respectively is equivalent to force of 100 N acting downwards at point C and couple of 200Nm. Find the magnitude and force F1 and F2 shown in the figure a.
![1160_Find the magnitude of force.png](https://www.expertsmind.com/CMSImages/1160_Find%20the%20magnitude%20of%20force.png)
The given system is converts to single force and single couple at point C. Let R be the resultant of forces F1 and F2.
RH = 0
RV = -F1 -F2
RV = -(F1 + F2) ...(i)
Since R = (R2v )1/2 = (F1 + F2)
Let the resultant R act at distance 'd' from point C.
Now the single force that is R is converted in to single force and couple at C
Now apply two equal and opposite force i.e. 'R' at point C. as shown in the figure b. Now force 'R' which act at point E and upward force which act at point C makes a couple of magnitude = Force × distance
= R × d
But R.d = 200 N-m
And force R which is downward direction = 100 N (negative for downward)
That is, (F1 + F2) = 100 or F1 + F2 = 100 ...(ii)
Now taking moment about C, or apply varignon's theorem.
R.d = 4F1 + 7F2 , but R.d = 200,
4F1 + 7F2 = 200 ...(iii)
By solving equation (ii)and (iii)
F1 = 500/3 N .......ANS
F2 = -200/3 N .......ANS