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Find the largest possible positive integer that will divide 398, 436, and 542 leaving remainder 7, 11, 15 respectively.
(Ans: 17)
Ans: The required number is the HCF of the numbers
Find the HCF of 391, 425 and 527 by Euclid's algorithm
∴ HCF (425, 391) = 17
Now we have to find the HCF of 17 and 527
527 = 17 ? 31 +0
∴ HCF (17,527) = 17
∴ HCF (391, 425 and 527) = 17
one half y minus 14
compare: 643,251: 633,512: 633,893. The answer is 633,512.
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Excuse me, would you give me main points on prime ideals to do project
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Give me an example , please : 1 over 2 , 14 over twenty-eight
7a^2+12a-11=0
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