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A shuttlecock used for playing badminton has the shape of a frustum of a Cone mounted on a hemisphere. The external diameters of the frustum are 5 cm and 2 cm, and the height of the entire shuttlecock is 7cm. Find the external surface area.(Ans: 74.26cm2)
Ans: r1 = radius of lower end of frustum = 1 cm
r2 = radius of upper end = 2.5 cm
l = = 6.18 cm
External surface area of shuttlecock = π (r1 + r2) l + 2π r2 1
On substituting we get, = 74.26 cm2
In a frequency distribution mode is 7.88, mean is 8.32 find the median. (Ans: 8.17) Ans: Mode = 3 median - 2 mean 7.88 = 3 median - 2 x 8.32 7.88 +16.64 = 3 median
Order to solve Mathematical Operations: Example: Solve the following equation: (4 - 2) + (3 x 4) - (10 ÷ 5) - 6 = ____________ Solution: a. Perform ma
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