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Find the distance of weight ‘x’ from support:
The two weights C = 2000N and D = 1000N are located on horizontal beam AB as shown in the figure given below. Find the distance of weight 'C' from support 'A' that is, 'X' so that support reaction at A is twice that at point B. (May-00-01)
Sol.: As given that RA = 2RB
∑H = 0 RAH = 0 ...(i) ∑V = 0
∑H = 0
RAH = 0 ...(i)
∑V = 0
RA + RB - 2000 - 1000 = 0
RA + RB = 3000N
But RA = 2RB
That is
RB = 1000N
...(ii)
RA = 2000N
...(iii)
By taking moment about point A:
∑MA = 2000 × x + 1000 × (x + 1) - RB × 4 = 0
2000 × x + 1000 × (x + 1) -1000 × 4 = 0
2000x + 1000x + 1000 - 4000 = 0
3000x = 3000
x = 1m .......ANS
I need a formula to calculate the offset that would give me
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