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In order to find the d-orbital splitting in a square planar complex, it is easier to start with an octahedral compound where splitting patterns are known and then imagine slowly moving two trans ligands away from the metal. This would at first distort the molecule which is known as tetragonally distorted octahedron. Moving the ligands further to such an extent I that the interaction between the metal ion and the ligands is practically nil would result in a square planar compound. This situation is best described its square planar complex because the other two ligands are so far off that they can be considered to be unattached to the metal ion and are thus unable to form a true chemical bond.
a metal forms 2 oxides. the higher oxide has 80% metal. 0.72g of lower oxide gave 0.8g of higher oxide when oxidised. show that law of multiple proportion is valid?
d orbital
Uses of Urea or Carbamide - Carboxylic Acids (a) Urea is used mainly as a nitrogen fertilizer. It has 46.4% nitrogen. (b) Urea is used in the manufacture of formaldehyde-ure
How to find the atomic structure of H
preparation of cycloalkanes
Q. Define the Normality of solutions? Ans. Sometime normality is used to measure concentration. Normality (abbreviated N) is the number of gram-equivalent masses of solute in 1
HOW MANY HALF LIVES ARE REQUIRED FOR THE CONCENTRATION OF REACTANT TO DECREASE BY 1.56 PERCENT OF ITS ORIGINAL VALUE
Explain oriental polarisation. Orientational Polarisation: When two different atoms form a chemical bond, one of the two is more probable to part with one or more of valence
defference between diffusion and osmosis
4-nitrotolouene ---> LiAlH 4 converts it to 4-aminotoluene ----> Add HNO 2 and it forms -----> diazonium salt ------> add H 3 PO 2 to get Toluene -----> add Br 2 /CCl 4 - 2
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