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Q. The radioactive isotope 84Pa214 undergoes a successive disintegration of two α decays and two β decays. Find the atomic number and the mass number of the resulting isotope.
For two α decays:
84Pa214 → 82 A 210 → 80 B 206
For two β decays :
80 B 206 → 81 C 206 → 82 D 206
The resulting isotope is direct with mass number 206 and atomic number 82
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