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Find speed of dynamo shaft:
Q: With the help of belt an engine running at 200rpm drives line shaft. The Diameter of the pulley on engine is 80cm and the diameter of the pulley on line shaft is 40cm. A 100cm diameter pulley on line shaft drives 20cm diameter pulley keyed to dynamo shaft. Find speed of dynamo shaft when: (1) There is no slip (2) There is a slip of 2.5 percent at each drive.
Sol:
Diameter of driver pulley (D1) = 80cm
Diameter of follower pulley (D2) = 40cm Diameter of driver pulley (D3) = 100cm Diameter of follower pulley (D4) = 20cm
Slip on each drive, s1 = s2 = 2.5
Let N4 = Speed of dynamo shaft
(i) When there is no slip
By using equation
N4/N1 = (D1.D3)/(D2.D4)
N4 = N1 X (D1.D3)/(D2.D4) = [(80 X 100) X 200]/(40 X 20)
N4 = 2000RPM .......ANS
(ii) When there is slip of 2.5 percent at each drive
In this case we will have equation of:
N4/N1 = [(D1.D3)/(D2.D4)][1-s1/100][1-s2/100] By putting the values, we get
proof of work being a path function
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