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Q. Illustrate how do you find the refractive index of a liquid by using total internal reflection?
Answer:-
Using Snell's law
n (1) = (n (2) x sin angle (2)) / sin angle (1).
n (1) = The refractive index of the greatly optically dense medium.
n (2) = The refractive index of the fewer optically dense medium.
angle (1) = The critical angle of the two mediums.
angle (2) = 90 degrees ever since when light is at the critical angle it undergoes total internal reflection.s
Since sin 90= 1 this is able to be ignored resulting in n (1) = n (2) / sin angle (1)
D=(a÷Sqrt(h**k**l**))
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