Already have an account? Get multiple benefits of using own account!
Login in your account..!
Remember me
Don't have an account? Create your account in less than a minutes,
Forgot password? how can I recover my password now!
Enter right registered email to receive password!
Q. Illustrate how do you find the refractive index of a liquid by using total internal reflection?
Answer:-
Using Snell's law
n (1) = (n (2) x sin angle (2)) / sin angle (1).
n (1) = The refractive index of the greatly optically dense medium.
n (2) = The refractive index of the fewer optically dense medium.
angle (1) = The critical angle of the two mediums.
angle (2) = 90 degrees ever since when light is at the critical angle it undergoes total internal reflection.s
Since sin 90= 1 this is able to be ignored resulting in n (1) = n (2) / sin angle (1)
Thermodynamic laws: First law of thermodynamics In internal energy of a system the change is the total heat transferred to or from the system & the work done on or by
Forward Characteristic of Zener diode Connect the circuit demonstrated in fig (a) using the 5.1 V zener diode. For forward characteristic, reverse the connection of zener di
Copper is completely miscible with (A) Nickel. (B) Gold. (C) Hydrogen. (D) Lead. Ans: Copper is completely miscible with gold.
A ball is thrown vertically upwards from the ground with a speed of 80 feet/second. In the English system of units, Determine the magnitude and direction of the acceleration
What are the basic block structure of communication system? What do you understand by sky wave propagation?
what are the advantages of using the thermo-electric thermometer over the mecury glass thermometer?
Explain 'drift velocity of free electrons'? Derive Ohm's law on the basis of the theory of electron drift.
Materials, which provide a path to the magnetic flux, are classified as (A) Insulating materials. (C) Magnetic materials. (B) Semi conducting materials. (D) Die
mass=volume * density.By using this formula we can find the mass of sphere. Volume of sphere=(4/3)pi*r^3 V=(4/3)*3.14*(1*10^-2)^3=4.187*10^-6 Mass=(4.187*10^-6)*900=3768*10^-6kg
Low resistivity materials: The conducting materials having resistivity between 10 -8 to 10 -6 ohm-m come under this category and are used in house wiring, as conductors for powe
Get guaranteed satisfaction & time on delivery in every assignment order you paid with us! We ensure premium quality solution document along with free turntin report!
whatsapp: +91-977-207-8620
Phone: +91-977-207-8620
Email: [email protected]
All rights reserved! Copyrights ©2019-2020 ExpertsMind IT Educational Pvt Ltd