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Find out the modulus of elasticity:
A unidirectional FRP is produced with fibre volume ratio of 60%. The density of fibre is 1480 kg/m3 and that of matrix is 1200 kg/m3. Calculate the weight percentages of matrix and fibre and the density of the composite. Also find out the modulus of elasticity of composite if Ef = 70 MPa, Em = 3 GPa.
Solution
Supposed that composite has a volume of 1 m3, so that
V f = 0.6 m3 and Vm = 0.4 m3
Mass of fibre = 1480 × 0.6 = 888 kg
And mass of matrix = 1200 × 0.4 = 480 kg
Mass of composite = 888 + 480 = 1368 kg
Density of composite = 1368 kg/1 m3 = 1368 kg/m3
Weight % of fibre = (888 /1368) × 100 = 64.9%
Weight % of matrix = 100 - 64.9 = 35.1
Modulus of elasticity of composite
E = V f E f + Vm Em
= 0.4 × 3 + 0.6 × 70
E = 43.2 MPa
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