Find out how much acid solution mixed, Mathematics

Assignment Help:

A chemist has one solution which is 50% acid and a second which is 25% acid. How much of each should be mixed to make 10 litres of 40% acid solution.                                                                                                                        (Ans:6L,4L)

Ans:    Let 50 % acids in the solution be x

Let 25 % of other solution be y

Total Volume in the mixture = x + y

A.P.Q:

x + y = 10                                     --------(1)

A.P.Q:

50/100 x  + 25/100y = (40/100) ×10

2x + y = 16    --------(2)

So x = 6 & y = 4

 


Related Discussions:- Find out how much acid solution mixed

Elementary row operations to reduce the augmented matrix, Consider the syst...

Consider the system of linear equations X + ay = 1 2x + 8y = b Where a and b are real numbers. (a)  Write out the augmented matrix for this system of linear equations.

Objective functions, For schedule consistency, you decide to require each o...

For schedule consistency, you decide to require each officer to report for their eight-hour shift at 12 AM, 4 AM, 8 AM, 12 PM, 4 PM, or 8 PM. As the Director of Public Safety, you

Explain identifying conic sections, Explain Identifying Conic Sections ...

Explain Identifying Conic Sections The graph of a quadratic equation in the variables x and y, like this one, x 2 + 3y 2 + 6y = -4, is a conic sections. There are three kind

If 967.234 is divided by 10 how will the decimal point move, If 967.234 is ...

If 967.234 is divided by 10, how will the decimal point move? It will move one place to the left. While dividing by multiples of 10, the decimal point is moved to the left acco

Quadratic equation, can anyone explain me the concept of quadratic equation...

can anyone explain me the concept of quadratic equation?

Probablity, probability as that of flipping a coin eight times and getting ...

probability as that of flipping a coin eight times and getting all the times the same side of the coin.)

Real and distinct roots, Now we start solving constant linear, coefficient ...

Now we start solving constant linear, coefficient and second order differential and homogeneous equations. Thus, let's recap how we do this from the previous section. We start alon

Write Your Message!

Captcha
Free Assignment Quote

Assured A++ Grade

Get guaranteed satisfaction & time on delivery in every assignment order you paid with us! We ensure premium quality solution document along with free turntin report!

All rights reserved! Copyrights ©2019-2020 ExpertsMind IT Educational Pvt Ltd