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A chemist has one solution which is 50% acid and a second which is 25% acid. How much of each should be mixed to make 10 litres of 40% acid solution. (Ans:6L,4L)
Ans: Let 50 % acids in the solution be x
Let 25 % of other solution be y
Total Volume in the mixture = x + y
A.P.Q:
x + y = 10 --------(1)
50/100 x + 25/100y = (40/100) ×10
2x + y = 16 --------(2)
So x = 6 & y = 4
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Consider the following interpolation problem: Find a quadratic polynomial p(x) such that p(x0) = y0 p’(x1) = y’1 , p(x2) = y2 where x0 is different from x2 and y0, y’1 , y2 a
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