Find out equation is a function, Mathematics

Assignment Help:

Example: Find out which of the following equations functions are & which are not functions.

                           y= 5x + 1

Solution

The "working" definition of function is saying is that if we take all of possible values of x & plug them in the equation & solve for y we will get accurately one value for each value of x.  At this stage it can be pretty hard to actually illustrate that an equation is a function thus we'll mostly talk our way through it. Conversely it's frequently quite easy to show that an equation isn't a function.

So, we need to illustrate that no matter what x we plug in the equation & solve for y we will only obtain a single value of y.  Note as well that the value of y will probably be different for each value of x, although it doesn't have to be.

Let's begin by plugging in some of the values of x and see what happens.

x= -4 : y= 5 ( -4) + 1 = -20 + 1 = -19

x= 0: y= 5 (0)+ 1 = 0 + 1 = 1

x= 10 : y= 5 (10) + 1 = 50 + 1= 51

Thus, for each value of x we obtained a single value of y out of the equation.  Now, it isn't enough to claim that this is a function.  To officially prove that it is a function we have to illustrates that this will work no matter that value of x we plug into the equation.

Certainly we can't plug all possible value of x in the equation. That just isn't possible physically.  For each x, on plugging in, first we multiplied the x by 5 and after that added 1 onto it.  Now, if we multiply any number by 5 we will obtain a single value from the multiplication.  Similarly, we will only get a single value if we add 1 onto a number. So, it seems plausible that depend on the operations involved with plugging x into the equation that we will just get a single value of y out of the equation.

Hence, this equation is a function.


Related Discussions:- Find out equation is a function

Solve by factorization, Solve by factorization X 2 +(a/a+b + a+b/a)x+...

Solve by factorization X 2 +(a/a+b + a+b/a)x+1 = 0 X 2 +(a/a+b + a+b/a)x+1 =>  X 2 +(a/a+b x a+b/ax + a/a+b .a+b/a) =>  X[x+a/a+b] +a+b/a[a+a*a+b]= 0 =>  X= -a

Product and quotient rule, Product and Quotient Rule : Firstly let's se...

Product and Quotient Rule : Firstly let's see why we have to be careful with products & quotients.  Assume that we have the two functions f ( x ) = x 3   and g ( x ) = x 6 .

Organized list strategy, i can not figer out my homework it says "USE THE M...

i can not figer out my homework it says "USE THE MAKE AN ORGANIZED LIST STRATEGY,Medeline bikes 4 laps around her neighborhood 2 times a week.How many laps does she bike in 8 weeks

Calculus, Properties of Integration

Properties of Integration

Decision-making under conditions of risk, Decision-making Under Conditions ...

Decision-making Under Conditions of Risk With decision-making under conditions of risk all possible states of nature are known and the decision maker has sufficient knowledge

Changing the base of the index, Changing The Base Of The Index For com...

Changing The Base Of The Index For comparison reasons if two series have different base years, this is difficult to compare them directly. In such cases, it is essential to ch

Shortcuts, pls told the maths shortcuts

pls told the maths shortcuts

Summation notation, SUMMATION NOTATION Under this section we require to...

SUMMATION NOTATION Under this section we require to do a brief review of summation notation or sigma notation.  We will start out with two integers, n and m, along with n a

Quantitative analysis, Suppose the economy is now ‘open’ and thus has an ex...

Suppose the economy is now ‘open’ and thus has an external demand (e.g. from the government, exports, etc.) of the dollar amounts for each respective industry. In the latest budget

Write Your Message!

Captcha
Free Assignment Quote

Assured A++ Grade

Get guaranteed satisfaction & time on delivery in every assignment order you paid with us! We ensure premium quality solution document along with free turntin report!

All rights reserved! Copyrights ©2019-2020 ExpertsMind IT Educational Pvt Ltd