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The sum of two consecutive odd integers is -112. What is the larger integer?
Two consecutive odd integers are numbers in order such as 3 and 5 or -31 and -29, that are each 2 numbers apart. In this problem you are searching for 2 consecutive odd integers. Let x = the ?rst and smallest consecutive odd integer. Let x + 2 = the second (and larger) consecutive negative odd integer. Sum is a key word for addition so the equation becomes (x)+ (x + 2) = -112. Combine such as terms on the left side of the equation: 2x + 2 = -112. Subtract 2 from both sides of the equation: 2x + 2 - 2 = -112 - 2; simplify: 2x = -114. Divide each side of the equation 2x = -114/2 by 2: 114/2 = 2/2. The variable is now alone: x = -57. Thus the larger value is: x + 2 = -55.
Example of Subtraction of Fractions: 1/3 + 1/6 + 1/8 = ____ Using trial & error we could search that 24 is the LCD or smallest number in which 3, 6, and 8 will all divide w
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I have about 6 Statistics questions, can anyone help me?
Solve the subsequent IVP. y′′ + 11y′ + 24 y = 0 y (0) =0 y′ (0)=-7 Solution The characteristic equation is as r 2 +11r + 24 = 0 ( r + 8) ( r + 3) = 0
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