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The sum of two consecutive odd integers is -112. What is the larger integer?
Two consecutive odd integers are numbers in order such as 3 and 5 or -31 and -29, that are each 2 numbers apart. In this problem you are searching for 2 consecutive odd integers. Let x = the ?rst and smallest consecutive odd integer. Let x + 2 = the second (and larger) consecutive negative odd integer. Sum is a key word for addition so the equation becomes (x)+ (x + 2) = -112. Combine such as terms on the left side of the equation: 2x + 2 = -112. Subtract 2 from both sides of the equation: 2x + 2 - 2 = -112 - 2; simplify: 2x = -114. Divide each side of the equation 2x = -114/2 by 2: 114/2 = 2/2. The variable is now alone: x = -57. Thus the larger value is: x + 2 = -55.
Whlie solving complex number 1pi in polar form.In book they have taken theta =-pi/4 why not 7pi/4 because the point lie in fourth quadrant and the theta is given by 2pi-angle(alpha
1. Find the third and fourth derivatives of the function Y=5x 7 +3x-6-17x -3 2. Find the Tangent to the curve Y= 5x 3 +2x-1 At the point where x = 2.
Need help figuring perimeter and area.
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