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Write a program to find the area under the curve y = f(x) between x = a and x = b, integrate y = f(x) between the limits of a and b. The area under a curve between two points can be found by doing a definite integral between the two points.
Solution :
#include float start_point, /* GLOBAL VARIABLES */ end_point, total_area; int numtraps; main( ) { void input(void); float find_area(float a,float b,int n); /* prototype */ print(“AREA UNDER A CURVE”); input( ); total_area = find_area(start_point, end_point, numtraps); printf(“TOTAL AREA = %f”, total_area); } void input(void) { printf(“\n Enter lower limit:”); scanf(“%f”, &start_point); printf(“Enter upper limit:”); scanf(“%f”, &end_point); printf(“Enter number of trapezoids:”); scanf(“%d”, &numtraps); } float find_area(float a, float b, int n) { floatbase, lower, h1, h2; /* LOCAL VARIABLES */ float function_x(float x); /* prototype */ float trap_area(float h1,float h2,floatbase);/*prototype*/ base = (b-1)/n; lower = a; for(lower =a; lower <= b-base; lower = lower + base) { h1 = function_x(lower); h1 = function_x(lower + base); total_area += trap_area(h1, h2, base); } return(total_area); float trap_area(float height_1,float height_2,floatbase) { float area; /* LOCAL VARIABLE */ area = 0.5 * (height_1 + height_2) * base; return(area); } float function_x(float x) { /* F(X) = X * X + 1 */ return(x*x + 1); } Output AREA UNDER A CURVE Enter lower limit: 0 Enter upper limit: 3 Enter number of trapezoids: 30 TOTAL AREA = 12.005000 AREA UNDER A CURVE Enter lower limit: 0 Enter upper limit: 3 Enter number of trapezoids: 100 TOTAL AREA = 12.000438
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A: No. Syntax wise it is permitted. But then the function is no longer Inline. Since the compiler will never know how deep the recursion is at compilation time.
area under curve pgm
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