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Now, let's get back to parabolas. There is a basic procedure we can always use to get a pretty good sketch of a parabola. Following it is. 1. Determine the vertex. We'll discus
how do we add integers
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Given that x=2 is a zero of P ( x ) = x 3 + 2x 2 - 5x - 6 determine the other two zeroes. Solution Firstly, notice that we actually can say the other two since we know th
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Solve following. |3x + 2| Solution Now we know that p ≥ 0 and thus can't ever be less than zero. Hence, in this case there is no solution as it is impos
(7x^3+6x^2)-2 -7x^3+6x^2-2 did I solve this correctly
resolve this a(x)=\/x-4+3
f(x)=-12x^2-24x+7
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